Yechim : Yechim : 29.12/22.4 = 1.3 mol 1.01*20 = 20.2 2x mol --------------------------- x mol 2CnH2n+1OH + Na -----> H2 30*1.3 + 2x ------------------------ = 20.2 1.3 + x X = 0.7 mol 103.6= x ---------------------- 0.7 mol 2CnH2n+1OH + Na -----> H2 148 = x ------------------------ 1 mol 2CnH2n+1OH = 148 1 mol CnH2n+1OH = 74 gr C4H9OH -----> C4H9--O--C4H9OH Mr = 130 #A 12 views13:30